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| Premium Member iTrader: (2) Join Date: Jan 2008 Location: Antarctica
Posts: 1,196
Spent time on board: 2 Weeks, 4 Days and 23:18:34
![]() | a = 0.15b * b + b a = 0.15b2 + b a = b + 0.15b2 a + -1b + -0.15b2 = b + -1b + 0.15b2 + -0.15b2 b + -1b = 0 a + -1b + -0.15b2 = 0 + 0.15b2 + -0.15b2 a + -1b + -0.15b2 = 0.15b2 + -0.15b2 0.15b2 + -0.15b2 = 0.00 a + -1b + -0.15b2 = 0.00 Now I'm confused! |
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| | #4 (permalink) | |
| Senior Member | Quote:
In my Formula , I substituted 1.5 for b , and that gives a = 1.8375 Therefore, if I substitute 1.8375 for a in your Formula Verad, then b should come up as 1.5 0.6 * 1.8375 = 1.1025 1 + 1.1025 = 2.1025 2.1025^1/2 = 1.45 -1 + 1.45 = .45 .45/.3 = 1.5 ![]() Thank You very much Verad. And thank you for your efforts as well IntelliGeorge. I don't suppose you could explain how you got the Formula Verad, in a similar way as how Intelligeorge tried to show? Not important as I have what I needed, but am curious, and Giving the Method is much more beneficial to the pupil than giving only the amswer. If you are busy I completely understand and very much appreciate what you have given regardless. Last edited by moeee : 11-04-08 at 05:47 PM. Reason: Added a Question | |
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| | #5 (permalink) |
| Senior Member | so how do you get " +/- " into a spreadsheet? Don't work on mine ? Using two columns for the formula ,one with + and the other with - I get different results, strange ? a with + b a with - (-1 + (1+0.6* B4)^1/2)/0.3 (-1 - (1+0.6* B4)^1/2)/0.3 4.33333 16.00000 -21.00000 8.33333 10.00000 -21.00000 9.33333 11.00000 -21.00000 369.33333 371.00000 -21.00000 -0.16667 1.50000 -21.00000 0.17083 1.83750 -21.00000 -1.66667 0 -21.00000 -1.66667 0 -21.00000 I gave up tryying to format this , its a joke Last edited by tytower : 13-04-08 at 09:11 AM. |
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| | #6 (permalink) | |
| Senior Member | Quote:
Probably won't work on mine either, but thats not what I put in mine. I just used the PLUS. It works fine and gives the correct answer. If instead I use the Minus, the answer comes out wrong. Verad was going a little on memory and perhaps his memory was almost perfect except for this little bit. I'm happy...and very grateful. ![]() | |
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| | #7 (permalink) |
| Premium Member | the formula verad gave is used to solve quadratic equations, ie your equation - of the form y = ax^2 + bx + c ------or in your case-------- a = 0.15b^2 + b I have attached a graph of your equation here: ![]() the roots of the equation are where the line crosses the horizontal axis - what you are looking for is the same thing essentially, just shifted up above / below the horizontal axis depending upon your value of a so, the +/- is supposed to be there, its just that it is not always a useful solution ![]() |
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